Bayes-and-Certainty.md

@@ -79,5 +79,7 @@ So one idea to handle this is to weigh the opinions as follows:
 
 For example, using 80.3% and 73%,
 
-1) $`P\_{bay} = {0.803(0.73)\over {0.803(0.73) + 0.197(0.27)}} = 0.917`$
-2) 
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+1) $`P\_{bay} = {0.803(0.73)\over {0.803(0.73) + 0.197(0.27)}} = 0.917$ (upper limit)
+2) $P\_{lo} = 0.803$ (lower limit)
+3) $f=10$
+4) $P_{comb,w} = 0.803 + 
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